Make xargs execute the command once for each line of input

Question

How can I make xargs execute the command exactly once for each line of input given? It\'s default behavior is to chunk the lines and execute the command once, passing multip

Answer 1

If you want to run the command for every line (i.e. result) coming from find, then what do you need the xargs for?

Try:

find path -type f -exec your-command {} \;

where the literal {} gets substituted by the filename and the literal \; is needed for find to know that the custom command ends there.

EDIT:

(after the edit of your question clarifying that you know about -exec)

From man xargs:

-L max-lines
Use at most max-lines nonblank input lines per command line. Trailing blanks cause an input line to be logically continued on the next input line. Implies -x.

Note that filenames ending in blanks would cause you trouble if you use xargs:

$ mkdir /tmp/bax; cd /tmp/bax
$ touch a\  b c\  c
$ find . -type f -print | xargs -L1 wc -l
0 ./c
0 ./c
0 total
0 ./b
wc: ./a: No such file or directory

So if you don't care about the -exec option, you better use -print0 and -0:

$ find . -type f -print0 | xargs -0L1 wc -l
0 ./c
0 ./c
0 ./b
0 ./a