Python - re.findall returns unwanted result

Question

re.findall(\"(100|[0-9][0-9]|[0-9])%\", \"89%\")

This returns only result [89] and I need to return the whole 89%. Any ideas how to do

Answer 1

Use an outer group, with the inner group a non-capturing group:

>>> re.findall("((?:100|[0-9][0-9]|[0-9])%)","89%")
['89%']