private inheritance

Question

I dont completely understand this:

class Base
{
    public:
    Base()
    {
        cout<<\"Base\" << endl;
    }

    virtual void call()
    {         


        

Answer 1

From a common understanding of inheritance, C++’ “private inheritance” is a horrible misnomer: it is not inheritance (as far as everything outside of the class is concerned) but a complete implementation detail of the class.

Seen from the outside, private inheritance is actually pretty much the same as composition. Only on the inside of the class do you get special syntax that is more reminiscent of inheritance than composition.

There’s a caveat though: C++ syntactically treats this as inheritance, with all the benefits and problems that this entails, such as scope visibility and accessibility. Furthermore, C-style casts (but no C++ cast!) actually ignores visibility and thus succeeds in casting your Derived pointer to Base:

Base* bPtr = (Base*) new Derived();

Needless to say, this is evil.