Unhandled Exception in Java

Question

I\'m currently in the process of learning how to properly do custom exception and I stumbled upon a problem. Whenever I try to utilize an object of a class that throws this

Answer 1

You are using the execute method, without creating a try-catch block for the RandomWiredException which it declares that it is throwing. Java required all checked exceptions (that extend Exception) to be properly handled by the caller - either with a try-catch block, or by adding throws to the calling method (in this case, it is main, though, so it shouldn't have a throws clause).

So the proper way to do it is like:

public class Main {
    public static void main(String[] args) {
        double x=Math.random();
        operation op=new operation();
        try {
            op.execute(x);
        } catch ( RandomWiredException e ) {
            e.printStackTrace();
            System.exit(1);
        }
    }
}

The actual code in the catch clause is up to your application's requirements, of course.

Note: use uppercase initial letter when you name classes. This is one of the Java styling conventions that will improve your code readability.