Getting the size of a malloc only with the returned pointer

Question

I want to be able to vary the size of my array so I create one this way:

int* array;
array = malloc(sizeof(int)*10);//10 integer elements

I

Answer 1

Use a pointer-to-array type rather than a pointer-to-element type:

int (*parray)[10] = malloc(sizeof *parray);

Then sizeof *parray gives you the desired answer, but you need to access the array using the * operator, as in (*parray)[i] (or equivalently albeit confusingly, parray[0][i]). Note that in modern C, 10 can be replaced with a variable.