How to run array_filter recursively in a PHP array?

Question

Given the following array $mm

Array
(
    [147] => Array
        (
            [pts_m] => 
            [pts_mreg] => 1
            [pts         


        

Answer 1

Should work

$count = array_sum(array_map(function ($item) {
  return ((int) !is_null($item['pts_m'])
       + ((int) !is_null($item['pts_mreg'])
       + ((int) !is_null($item['pts_cg']);
}, $array);

or maybe

$count = array_sum(array_map(function ($item) {
  return array_sum(array_map('is_int', $item));
}, $array);

There are definitely many more possible solutions. If you want to use array_filter() (without callback) remember, that it treats 0 as false too and therefore it will remove any 0-value from the array.

If you are using PHP in a pre-5.3 version, I would use a foreach-loop

$count = 0;
foreach ($array as $item) {
  $count += ((int) !is_null($item['pts_m'])
          + ((int) !is_null($item['pts_mreg'])
          + ((int) !is_null($item['pts_cg']);
}

---

Update

Regarding the comment below:

Thx @kc I actually want the method to remove false, 0, empty etc

When this is really only, what you want, the solution is very simple too. But now I don't know, how to interpret

My expected result here would be 5.

Anyway, its short now :)

$result = array_map('array_filter', $array);
$count = array_map('count', $result);
$countSum = array_sum($count);

The resulting array looks like

Array
(
[147] => Array
    (
        [pts_mreg] => 1
        [pts_cg] => 1
    )    
[158] => Array
    (
    )

[159] => Array
    (
        [pts_mreg] => 1
        [pts_cg] => 1
    )

)