I have a char array buffer that I am using to store characters that the user will input one by one. My code below works but has a few glitches that I can\'t figure out:
The only thing you are passing to the printf() function is a pointer to the first character of your string. printf() has no way of knowing the size of your array. (It doesn't even know if it's an actual array, since a pointer is just a memory address.)
printf() and all the standard c string functions assume that there is a 0 at the end of your string. printf() for example will keep printing characters in memory, starting at the char that you pass to the function, until it hits a 0.
Therefore you should change your code to something like this:
char Buffer[9]; //holds the byte stream
int i=0;
if( //user input event has occured )
{
Buffer[i] = charInput;
i++;
Buffer[i] = 0; // You can also assign the char '\0' to it to get the same result.
// Display a response to input
printf("Buffer is %s!\n", Buffer);
}