How to save XLSM file with Macro, using openpyxl

Question

I have .xlsm file with a Macro function. I\'m loading it using openpyxl and write some data to the file and finally want t

Answer 1

I don't know if this is still relevant for the person that asked the question, but I am dealing with the same problem and found a possible solution.

1. open the original file (say: 1.xlsm) and do magic with openpyxl;
2. save as 2.xlsx;
3. both files are actually zipped files: extract them to a temporary directory;
4. copy files from the directory of the original file to the directory of the xlsx files: one of the files is the macro (vbaProject.bin) and 2 of the files are necessary because they describe the type of the file among other things;
5. put all of the files that belong to the xlsx directory back into a zip file and rename this from zip to xlsm. This file contains the original macro and has been edited with openpyxl;
6. (Optional) delete the two temporary directories and the 2.xlsx file.

Example code:

import openpyxl
import zipfile
from shutil import copyfile
from shutil import rmtree
import os

PAD = os.getcwd()

wb = openpyxl.load_workbook('1.xlsm')

#####
# do magic with openpyxl here and save
ws = wb.worksheets[0]
ws.cell(row=2, column=3).value = 'Edited'   # example
#####

wb.save('2.xlsx')


with zipfile.ZipFile('1.xlsm', 'r') as z:
    z.extractall('./xlsm/')

with zipfile.ZipFile('2.xlsx', 'r') as z:
    z.extractall('./xlsx/')

copyfile('./xlsm/[Content_Types].xml','./xlsx/[Content_Types].xml')
copyfile('./xlsm/xl/_rels/workbook.xml.rels','./xlsx/xl/_rels/workbook.xml.rels')
copyfile('./xlsm/xl/vbaProject.bin','./xlsx/xl/vbaProject.bin')

z = zipfile.ZipFile('2.zip', 'w')

os.chdir('./xlsx')

for root, dirs, files in os.walk('./'):
        for file in files:
            z.write(os.path.join(root, file))
z.close()

#clean
os.chdir(PAD)
rmtree('./xlsm/')
rmtree('./xlsx/')
os.remove('./2.xlsx')
os.rename('2.zip', '2.xlsm')