How to print the address of a function?

Question

I let gcc compile the following example using -Wall -pedantic:

#include 

int main(void)
{
  printf(\"main: %p\\n\",         


        

Answer 1

While converting a function pointer to a void pointer is technically dangerous, converting function pointers to void pointers is used in the POSIX standard, so it is almost sure to work on most compilers.

Look up dlsym().