How to print the address of a function?

Question

I let gcc compile the following example using -Wall -pedantic:

#include 

int main(void)
{
  printf(\"main: %p\\n\",         


        

Answer 1

This is essentially the only portable way to print a function pointer.

size_t i;
int (*ptr_to_main)() = main;
for (i=0; i