standard conversions: Array-to-pointer conversion

Question

This is the point from ISO :Standard Conversions:Array-to-pointer conversion: $4.2.1

An lvalue or rvalue of type “array of N T” or “array o

Answer 1

This means, that you can have the following situation:

int arr[100];
arr[ 0 ] = arr[ 1 ] = 666;
// ..

You can use arr as pointer to int, which points to the first element of the array, for example:

*arr = 123;

and then the array will be: arr = { 123, 666, ... }

Also, you could pass the array to a function, that takes int*:

void f( int* a ) { /* ... */ }

and call it:

f( arr );

It's absolutely the same as calling it like this:

f( &arr[ 0 ] );

That is what The result is a pointer to the first element of the array. means.

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Another way, you could use the address of the first element is:

*( &arr[ 0 ] + 1 ) = 222;

this will make the second element in the array with value 222; It's the same as

arr[1] = 222;

and

*( arr + 1 ) = 222;