2D-array as argument to function

Question

Why can\'t you declare a 2D array argument in a function as you do with a normal array?

 void F(int bar[]){} //Ok
 void Fo(int bar[][]) //Not ok
 void Foo(in         


        

Answer 1

Because when you pass an array, it decays to a pointer, so excluding the outer-most dimension is ok and that's the only dimension you can exclude.

 void Foo(int bar[][SIZE]) 

is equivalent to:

 void Foo(int (*bar)[SIZE])