Do stateless random number generators exist?

Question

Is there a difference between generating multiple numbers using a single random number generator (RNG) versus generating one number per generator and discarding it? Do both

Answer 1

It's worth mentioning that Haskell is a language which attempts to entirely eliminate mutable state. In order to reconcile this goal with hard-requirements like IO (which requires some form of mutability), monads must be used to thread state from one calculation to the next. In this way, Haskell implements its pseudo-random number generator. Strictly speaking, generating random numbers is an inherently stateful operation, but Haskell is able to hide this fact by moving the state "mutation" into the bind (>>=) operation.

This probably sounds a little abstract, and it doesn't really answer your question completely, but I think it is still applicable. From a theoretical standpoint, it is impossible to work with a RNG without involving state. Regardless, there are techniques which can be used to mitigate this interaction and make it appear as if the entire operation is of a stateless nature.