Handle generator exceptions in its consumer

Question

This is a follow-up to Handle an exception thrown in a generator and discusses a more general problem.

I have a function that reads data in different formats. All fo

Answer 1

About your point of propagating exception from generator to consuming function, you can try to use an error code (set of error codes) to indicate the error. Though not elegant that is one approach you can think of.

For example in the below code yielding a value like -1 where you were expecting a set of positive integers would signal to the calling function that there was an error.

In [1]: def f():
  ...:     yield 1
  ...:     try:
  ...:         2/0
  ...:     except ZeroDivisionError,e:
  ...:         yield -1
  ...:     yield 3
  ...:     


In [2]: g = f()

In [3]: next(g)
Out[3]: 1

In [4]: next(g)
Out[4]: -1

In [5]: next(g)
Out[5]: 3