How to avoid console window with .pyw file containing os.system call?

Question

If I save my code files as .pyw, no console window appears - which is what I want - but if the code includes a call to os.system, I still get a pes

Answer 1

People are a bit lazy... I would thx @Piotr Dobrogost and @Frank S. Thomas for their answers.

I came with this code who is runinng on Linux and Windows:

import platform
import subprocess
startupinfo = None
if platform.system() == 'Windows':
    import _subprocess  # @bug with python 2.7 ?
    startupinfo = subprocess.STARTUPINFO()
    startupinfo.dwFlags |= _subprocess.STARTF_USESHOWWINDOW
    startupinfo.wShowWindow = _subprocess.SW_HIDE

Later...

args = [exe, ...]
out = subprocess.check_output(args, startupinfo=startupinfo)

Thx guys ;)

Additionally: just to note that the following code using 'call' also works on Python 2.7 (on Windows) with the 'startupinfo' code above:

def run_command(cmd, sin, sout):
    print "Running cmd : %s"%(" ".join(cmd) )
    return subprocess.call( cmd, stdin=sin, stdout=sout, startupinfo=startupinfo)