uint8_t can't be printed with cout

Question

I have a weird problem about working with integers in C++.

I wrote a simple program that sets a value to a variable and then prints it, but it is not working as expe

Answer 1

The operator<<() overload between istream and char is a non-member function. You can explicitly use the member function to treat a char (or a uint8_t) as an int.

#include 
#include 

int main()
{
   uint8_t aa=5;

   std::cout << "value is ";
   std::cout.operator<<(aa);
   std::cout << std::endl;

   return 0;
}

Output:

value is 5