How to sort IP addresses stored in dictionary in Python?

Question

I have a piece of code that looks like this:

ipCount = defaultdict(int)

for logLine in logLines:
    date, serverIp, clientIp = logLine.split(\" \")
    ipC         


        

Answer 1

how about not working with strings at all and instead convert each octet into integer, then passing it into 4 dimensional dictionary?

ClientIps[192][168][102][105]=1
ClientIps[192][168][99][11]=1

then it is easy to just sort an array by key, isnt it?

for key1, value in sorted(ClientIps.items()): 
  for key2, value in sorted(ClientIps[key1].items()): 
    for key3, value in sorted(ClientIps[key1][key2].items()): 
      for key4, value in sorted(ClientIps[key][key2][key3].items()): 
        print(key1, key2, key3, key4)

for speed reasons it may be beneficial to also compare simple python dictionary against OrderedDict .