Java overloading and overriding

Question

We always say that method overloading is static polymorphism and overriding is runtime polymorphism. What exactly do we mean by static here? Is the call to a method resolved

Answer 1

Method overloading means making multiple versions of a function based on the inputs. For example:

public Double doSomething(Double x) { ... }
public Object doSomething(Object y) { ... }

The choice of which method to call is made at compile time. For example:

Double obj1 = new Double();
doSomething(obj1); // calls the Double version

Object obj2 = new Object();
doSomething(obj2); // calls the Object version

Object obj3 = new Double();
doSomething(obj3); // calls the Object version because the compilers see the 
                   // type as Object
                   // This makes more sense when you consider something like

public void myMethod(Object o) {
  doSomething(o);
}
myMethod(new Double(5));
// inside the call to myMethod, it sees only that it has an Object
// it can't tell that it's a Double at compile time

Method Overriding means defining a new version of the method by a subclass of the original

class Parent {
  public void myMethod() { ... }
}
class Child extends Parent {
  @Override
  public void myMethod() { ... }
}

Parent p = new Parent();
p.myMethod(); // calls Parent's myMethod

Child c = new Child();
c.myMethod(); // calls Child's myMethod

Parent pc = new Child();
pc.myMethod(); // call's Child's myMethod because the type is checked at runtime
               // rather than compile time

I hope that helps