Confusion between isNaN and Number.isNaN in javascript

Question

I have a confusion in how NaN works. I have executed isNaN(undefined) it returned true . But if I will use Number.isNaN(undefined) it

Answer 1

I found that if you want to check if something is numbery (or not), then a combination of Number.isNaN() with either Number.parseInt() or Number.parseFloat() (depending on what you expect) to cover most use cases:

consider: test a bunch of different input vars against several is number tests:

r = [NaN, undefined, null, false, true, {}, [], '', ' ', 0, 1, '0', '1']
.map(function(v){return [
    v, 
    isNaN(v), 
    Number.isNaN(v), 
    Number.isInteger(v),
    Number.parseInt(v, 10), 
    Number.isNaN( Number.parseInt(v, 10)) 
];});
console.table(r);
// or if console.table() not available:
r.join('\n', function(v){v.join(',')} );

result:

NaN      , true , true , false, NaN, true 
undefined, true , false, false, NaN, true 
null     , false, false, false, NaN, true 
false    , false, false, false, NaN, true 
true     , false, false, false, NaN, true 
Object   , true , false, false, NaN, true 
Array(0) , false, false, false, NaN, true 
''       , false, false, false, NaN, true 
' '      , false, false, false, NaN, true 
0        , false, false, true , 0  , false
1        , false, false, true , 1  , false
'0'      , false, false, false, 0  , false
'1'      , false, false, false, 1  , false

Note the last column, which is usually what I want in my experience.