I am trying to take a string of text like so:
$string = \"This (1) is (2) my (3) example (4) text\";
In every instance where there is a pos
You are almost there. You are using:
$result = preg_replace("((\d+))", "$0", $string);
preg_* family of function
should be delimited in pair of
delimiters. Since you are not using
any delimiters you get that error.( and ) are meta char in a regex,
meaning they have special meaning.
Since you want to match literal open
parenthesis and close parenthesis,
you need to escape them using a \.
Anything following \ is treated
literally.\d+. But the captured
integer will be in $1 and not $0. $0
will have the entire match, that is
integer within parenthesis.If you do all the above changes you'll get:
$result = preg_replace("#\((\d+)\)#", "$1", $string);