How typedef works for function pointers

Question

I think I may be suffering from the dreaded \"accidental programmer\" disease, at least when it comes to typedefs and function pointers. So I\'ve been experimenting with all

Answer 1

Like C, C++ has pointer to functions: void (*)() for example is a pointer to a function that takes no argument and returns no value. However, C++ has also introduced references to functions void (&)() and there are implicit conversions between the two (though I don't remember the rules exactly).

Therefore:

• funcname is a reference to function
• &funcname is a pointer to function

Note that taking the address (or a reference to) a function that is overloaded requires a static_cast to the exact type (to resolve the overload).