How do I use a new-line replacement in a BSD sed?

Question

Greetings, how do I perform the following in BSD sed?

sed \'s/ /\\n/g\'

From the man-page it states that \\n will be treated literally with

Answer 1

For ease of use, i personally often use

cr="\n" 
# or (depending version and OS)
cr="
"

sed "s/ /\\${cr}/g"

so it stays on 1 line.