How do I use a new-line replacement in a BSD sed?

Question

Greetings, how do I perform the following in BSD sed?

sed \'s/ /\\n/g\'

From the man-page it states that \\n will be treated literally with

Answer 1

In a shell, you can do:

    sed 's/ /\
/g'

hitting the enter key after the backslash to insert a newline.