How to get an age from a D.O.B field in MySQL?

Question

I need to calculate the age of a \"customer\" from their date of birth.

I have tried to use the following:

DATEDIFF(year, customer.dob, \"2010

Answer 1

Assumed the given date is greater than the current date,

1.Find the total no of days b/w the current date and the given date.

-> DATEDIFF(NOW(),'1988-05-01')

2.Find the no of years from the calculated no of days.

-> DATEDIFF(NOW(),'1988-05-01')/365.25

3.The age should be the completed no of years by a person. To get it, we can use 'floor' to the calculated no of years.

-> FLOOR(DATEDIFF(NOW(),'1988-05-01')/365.25)

Example: SELECT FLOOR(DATEDIFF(NOW(),'1988-05-01')/365.25) AS age;