ORDER BY DATE showing NULLS first then most recent dates

Question

I have a stored procedure which executes a select statement. I would like my results ordered by a date field and display all records with NULL dates first and then the most

Answer 1

I know this is old, but when I found it I noticed the accepted solution, https://stackoverflow.com/a/821856/7177892, could be simplified by making the result of the CASE statement be either today (GETDATE()) or the actual date.

Original:

ORDER BY (CASE WHEN [Submission Date] IS NULL THEN 1 ELSE 0 END) DESC, 
         [Submission Date] DESC

Simplified:

ORDER BY (CASE WHEN [Submission Date] IS NULL 
               THEN GETDATE() 
               ELSE [Submission Date] 
          END) DESC