Given a the following table:
Index | Element
---------------
1 | A
2 | B
3 | C
4 | D
We want to generate all th
Just using SQL, without any code, you could do it if you can crowbar yourself another column into the table. Clearly you need to have one joined table for each of the values to be permuted.
with llb as (
select 'A' as col,1 as cnt union
select 'B' as col,3 as cnt union
select 'C' as col,9 as cnt union
select 'D' as col,27 as cnt
)
select a1.col,a2.col,a3.col,a4.col
from llb a1
cross join llb a2
cross join llb a3
cross join llb a4
where a1.cnt + a2.cnt + a3.cnt + a4.cnt = 40