Get color of each pixel of an image using BufferedImages

Question

I am trying to get every single color of every single pixel of an image. My idea was following:

int[] pixels;
BufferedImage image;

image = ImageIO.read(this         


        

Answer 1

import javax.imageio.ImageIO;
import java.awt.image.BufferedImage;
import java.io.File;
import java.io.IOException;

public class Main {
    public static void main(String[] args) throws IOException {
        BufferedImage bufferedImage = ImageIO.read(new File("norris.jpg"));
        int height = bufferedImage.getHeight(), width = bufferedImage.getWidth();
        for (int y = 0; y < height; y++) {
            for (int x = 0; x < width; x++) {
                int RGBA = bufferedImage.getRGB(x, y);
                int alpha = (RGBA >> 24) & 255;
                int red = (RGBA >> 16) & 255;
                int green = (RGBA >> 8) & 255;
                int blue = RGBA & 255;
            }
        }
    }
}

Assume the buffered image represents an image with 8-bit RGBA color components packed into integer pixels, I search for "RGBA color space" on wikipedia and found following:

In the byte-order scheme, "RGBA" is understood to mean a byte R, followed by a byte G, followed by a byte B, and followed by a byte A. This scheme is commonly used for describing file formats or network protocols, which are both byte-oriented.

With simple Bitwise and Bitshift you can get the value of each color and the alpha value of the pixel.

Very interesting is also the other order scheme of RGBA:

In the word-order scheme, "RGBA" is understood to represent a complete 32-bit word, where R is more significant than G, which is more significant than B, which is more significant than A. This scheme can be used to describe the memory layout on a particular system. Its meaning varies depending on the endianness of the system.