Using case for a range of numbers in Bash

Question

I am trying to do the following using case in Bash (in Linux).

If X is between 460 and 660, output X information.

If X is between 661 and 800, d

Answer 1

I was looking for the simplest solution and found it difficult to use a case statement with a number range .

Finally i found a really simple solution for zsh :

  #!/usr/bin/zsh 

 case "${var}" in

 <0-5461>)

 printf "${var} is between 0 and 5461"

 ;;

 <5462-10922>)

printf "${var} is between 5462-10922"

 ;;

 esac

and for Bash :

  #!/bin/bash

 case $((   

(var >= 0 && var <= 5461)      * 1 +   

(var > 5462 && var  <= 10922)   * 2)) in   

(1) printf "${var} is between 0 and 5461";; 

(2) printf "${var} is between 5461 and 10922";; 

esac

Hope it helps someone .