Using case for a range of numbers in Bash

Question

I am trying to do the following using case in Bash (in Linux).

If X is between 460 and 660, output X information.

If X is between 661 and 800, d

Answer 1

Similar issue which might be useful to someone ... Random additional thing I just tried out where it checks also that it is an integer, for me I wanted it to have a preset value, let the user change it, if they input the wrong data it sets to default.

    func_set_num_files(){
        echo "How many files do you want to create? (input a number 1-10000)"
        read X
        # 1, is it a number, #2 is it within max range?
        if [[ $X != *[!0-9]* ]]; then

            if ((1<=X && X<=10000)) ;then
                        echo "NUM_FILES=$X"
                        NUM_FILES=$X
                else
                        echo "Invalid input, setting to default value [ $NUM_FILES ].";sleep 3
            fi

        else
            echo "Invalid input, non-numeric values entered, setting to default value [ $NUM_FILES ].";sleep 3
        fi

    }

Another example using 'case' to check that a variable is in a range of integers :

check that $MAX is a number and that it's between 50-100 :

            case $MAX in
                ''|*[!0-9]*)
                    echo "The value $MAX is not a number !"
                    exit 1
                ;;
                *)
                    if [ $MAX -lt 50 ] || [ $MAX -gt 100 ] ;then
                        echo "The value $MAX is not between 50-100"
                        exit 1
                    fi
                    echo "Looks like we are good !"
                ;;
            esac