Whats the way to simplify something like the following code example? I can\'t find the right operator.. could anyone give a short example?
this.returnsObserv
Previously answered for RxJS 5, I ended up on this page whilst using 6.
In the case you're on 6 as well (and I think you should be by now) you can use flatmap as an operator within pipe.
Modified the example code of @user3743222:
this.returnsObservable1(...)
.pipe(
flatMap(success => this.returnsObservable2(...)),
flatMap(success => this.returnsObservable3(...))
)
.subscribe(success => {(...)});