Following on from my other comment, here's a batch file which displays the current JRE or JDK based on the registry values.
It's different from the other solutions in instances where java is installed, but not on the PATH.
@ECHO off
SET KIT=JavaSoft\Java Runtime Environment
call:ReadRegValue VER "HKLM\Software\%KIT%" "CurrentVersion"
IF "%VER%" NEQ "" GOTO FoundJRE
SET KIT=Wow6432Node\JavaSoft\Java Runtime Environment
call:ReadRegValue VER "HKLM\Software\%KIT%" "CurrentVersion"
IF "%VER%" NEQ "" GOTO FoundJRE
SET KIT=JavaSoft\Java Development Kit
call:ReadRegValue VER "HKLM\Software\%KIT%" "CurrentVersion"
IF "%VER%" NEQ "" GOTO FoundJRE
SET KIT=Wow6432Node\JavaSoft\Java Development Kit
call:ReadRegValue VER "HKLM\Software\%KIT%" "CurrentVersion"
IF "%VER%" NEQ "" GOTO FoundJRE
ECHO Failed to find Java
GOTO :EOF
:FoundJRE
call:ReadRegValue JAVAPATH "HKLM\Software\%KIT%\%VER%" "JavaHome"
ECHO %JAVAPATH%
GOTO :EOF
:ReadRegValue
SET key=%2%
SET name=%3%
SET "%~1="
SET reg=reg
IF DEFINED ProgramFiles(x86) (
IF EXIST %WINDIR%\sysnative\reg.exe SET reg=%WINDIR%\sysnative\reg.exe
)
FOR /F "usebackq tokens=3* skip=1" %%A IN (`%reg% QUERY %key% /v %name% 2^>NUL`) DO SET "%~1=%%A %%B"
GOTO :EOF
