Currently i am working on an application that splits a long column into short ones. For that i split the entire text into words, but at the moment my regex splits numbers to
str.replace(/([.?!])\s*(?=[A-Z])/g, "$1|").split("|")
Output:
[ 'This is a long string with some numbers [125.000,55 and 140.000] and an end.',
'This is another sentence.' ]
Breakdown:
([.?!]) = Capture either . or ? or !
\s* = Capture 0 or more whitespace characters following the previous token ([.?!]). This accounts for spaces following a punctuation mark which matches the English language grammar.
(?=[A-Z]) = The previous tokens only match if the next character is within the range A-Z (capital A to capital Z). Most English language sentences start with a capital letter. None of the previous regexes take this into account.
The replace operation uses:
"$1|"
We used one "capturing group" ([.?!]) and we capture one of those characters, and replace it with $1 (the match) plus |. So if we captured ? then the replacement would be ?|.
Finally, we split the pipes | and get our result.
So, essentially, what we are saying is this:
1) Find punctuation marks (one of . or ? or !) and capture them
2) Punctuation marks can optionally include spaces after them.
3) After a punctuation mark, I expect a capital letter.
Unlike the previous regular expressions provided, this would properly match the English language grammar.
From there:
4) We replace the captured punctuation marks by appending a pipe |
5) We split the pipes to create an array of sentences.