According to the most programming languages scope rules, I can access variables that are defined outside of functions inside them, but why doesn\'t this code work?
PHP can be frustrating for this reason. The answers above using global
did not work for me, and it took me awhile to figure out the proper use of use
.
This is correct:
$functionName = function($stuff) use ($globalVar) {
//do stuff
}
$output = $functionName($stuff);
$otherOutput = $functionName($otherStuff);
This is incorrect:
function functionName($stuff) use ($globalVar) {
//do stuff
}
$output = functionName($stuff);
$otherOutput = functionName($otherStuff);
Using your specific example:
$data = 'My data';
$menugen = function() use ($data) {
echo "[" . $data . "]";
}
$menugen();