Avoiding problems with JavaScript's weird decimal calculations

Question

I just read on MDN that one of the quirks of JS\'s handling of numbers due to everything being \"double-precision 64-bit format IEEE 754 values\" is that when you d

Answer 1

In situations like these you would tipically rather make use of an epsilon estimation.

Something like (pseudo code)

if (abs(((.2 + .1) * 10) - 3) > epsilon)

where epsilon is something like 0.00000001, or whatever precision you require.

Have a quick read at Comparing floating point numbers