Dynamically arranging divs using jQuery

Answer 1

[Edit], This is tested and works:

var order = [3,2,1,4];
var container = $("#container");
var children = container.children();
container.empty();
for (var i = 0; i < order.length; i++){
    container.append(children[order[i]-1])
}

The i-1 is necessary since your ordering starts at 1 but arrays are indexed from 0.

Thanks to J-P and Russ Cam for making me look at it again.