Python: return the index of the first element of a list which makes a passed function true

Question

The list.index(x) function returns the index in the list of the first item whose value is x.

Is there a function, list_func_index()

Answer 1

you could do this with a list-comprehension:

l = [8,10,4,5,7]
filterl = [a for a in l if a % 2 != 0]

Then filterl will return all members of the list fulfilling the expression a % 2 != 0. I would say a more elegant method...