PHP pass function name as param then call the function?

Question

I need to pass a function as a parameter to another function and then call the passed function from within the function...This is probably easier for me to explain in code..

Answer 1

function foo($function) {
  $function(" World");
}
function bar($params) {
  echo "Hello".$params;
}

$variable = 'bar';
foo($variable);

Additionally, you can do it this way. See variable functions.