How to check if a Javascript Class inherits another (without creating an obj)?

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别那么骄傲
别那么骄傲 2020-11-29 03:12

Eg:

function A(){}
function B(){}
B.prototype = new A();

How can I check if the class B inherits class A?

5条回答
  •  心在旅途
    2020-11-29 03:46

    Gotchas: Note that instanceof does not work as expected if you use multiple execution contexts/windows. See §§.


    Also, per https://johnresig.com/blog/objectgetprototypeof/, this is an alternative implementation that is identical to instanceof:

    function f(_, C) { // instanceof Polyfill
      while (_ != null) {
        if (_ == C.prototype)
          return true;
        _ = _.__proto__;
      }
      return false;
    }
    

    Modifying it to check the class directly gives us:

    function f(ChildClass, ParentClass) {
      _ = ChildClass.prototype;
      while (_ != null) {
        if (_ == C.prototype)
          return true;
        _ = _.__proto__;
      }
      return false;
    }
    


    Sidenote

    instanceof itself checks if obj.proto is f.prototype, thus:

    function A(){};
    A.prototype = Array.prototype;
    []instanceof Array // true
    

    and:

    function A(){}
    _ = new A();
    // then change prototype:
    A.prototype = [];
    /*false:*/ _ instanceof A
    // then change back:
    A.prototype = _.__proto__
    _ instanceof A //true
    

    and:

    function A(){}; function B(){};
    B.prototype=Object.prototype;
    /*true:*/ new A()instanceof B 
    

    If it's not equal, proto is swapped with proto of proto in the check, then proto of proto of proto, and so on. Thus:

    function A(){}; _ = new A()
    _.__proto__.__proto__ = Array.prototype
    g instanceof Array //true
    

    and:

    function A(){}
    A.prototype.__proto__ = Array.prototype
    g instanceof Array //true
    

    and:

    f=()=>{};
    f.prototype=Element.prototype
    document.documentElement instanceof f //true
    document.documentElement.__proto__.__proto__=[];
    document.documentElement instanceof f //false
    

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