Difference between “pointer to int” and “pointer to array of ints”

Question

int main()
{
    int (*x)[5];                 //pointer to an array of integers
    int y[6] = {1,2,3,4,5,6};    //array of integers
    int *z;                              


        

Answer 1

#include

int main(void)
{
    int (*x)[6];                 //pointer to an array of integers
    int y[6] = {11,22,33,44,55,66};    //array of integers
    int *z;                      //pointer to integer
    int i;

    z = y;
    for(i = 0;i<6;i++)
        printf("%d ",z[i]);
    printf("\n");

    x = &y;

    for(int j = 0;j<6;j++)
        printf("%d ",*(x[0]+j));

    return 0;
}

//OUTPUT::

11 22 33 44 55 66

11 22 33 44 55 66

Pointer to an array are best suitable for multi-dimensional array. but in above example we used single dimension array. so, in the second for loop we should use (x[0]+j) with * to print the value. Here, x[0] means 0th array. And when we try to print value using printf("%d ",x[i]); you will get 1st value is 11 and then some garbage value due to trying to access 1st row of array and so on.