batch script - read line by line

Question

I have a log file which I need to read in, line by line and pipe the line to a next loop.

Firstly I grep the logfile for the \"main\" word (like \"error\") in a sep

Answer 1

The "call" solution has some problems.

It fails with many different contents, as the parameters of a CALL are parsed twice by the parser.
These lines will produce more or less strange problems

one
two%222
three & 333
four=444
five"555"555"
six"&666
seven!777^!
the next line is empty

the end

Therefore you shouldn't use the value of %%a with a call, better move it to a variable and then call a function with only the name of the variable.

@echo off
SETLOCAL DisableDelayedExpansion
FOR /F "usebackq delims=" %%a in (`"findstr /n ^^ t.txt"`) do (
    set "myVar=%%a"
    call :processLine myVar
)
goto :eof

:processLine
SETLOCAL EnableDelayedExpansion
set "line=!%1!"
set "line=!line:*:=!"
echo(!line!
ENDLOCAL
goto :eof