How to print an unsigned char in C?

Question

I am trying to print char as positive value:

char ch = 212;
printf(\"%u\", ch);

but I get:

4294967252

How

Answer 1

Because char is by default signed declared that means the range of the variable is

-127 to +127>

your value is overflowed. To get the desired value you have to declared the unsigned modifier. the modifier's (unsigned) range is:

 0 to 255

to get the the range of any data type follow the process 2^bit example charis 8 bit length to get its range just 2 ^(power) 8.