Parse Date in Bash

Question

How would you parse a date in bash, with separate fields (years, months, days, hours, minutes, seconds) into different variables?

The date format is: YYYY-MM-D

Answer 1

instead of using the shell scripting,incorporate in your scripting itself like below wheever you need:

a=date +%Y 
b=date +%S
c=date +%H

a will be year b will be seconds c will be hours. and so on.