How to show a custom UIMenuItem for a UITableViewCell?

Question

I want the UIMenuController that pops up when I long-press a UITableViewCell to show custom UIMenuItems.

I set up the custom item in viewDidLoad

UIMe         


        

Answer 1

To implement copy and a custom action for UITableViewCell:

Once in your application, register the custom action:

struct Token { static var token: dispatch_once_t = 0 }
dispatch_once(&Token.token) {
    let customMenuItem = UIMenuItem(title: "Custom", action: #selector(MyCell.customMenuItemTapped(_:))
    UIMenuController.sharedMenuController().menuItems = [customMenuItem]
    UIMenuController.sharedMenuController().update()
}

In your UITableViewCell subclass, implement the custom method:

func customMenuItemTapped(sender: UIMenuController) {
    // implement custom action here
}

In your UITableViewDelegate, implement the following methods:

override func tableView(tableView: UITableView, shouldShowMenuForRowAtIndexPath indexPath: NSIndexPath) -> Bool {
    return true
}

override func tableView(tableView: UITableView, canPerformAction action: Selector, forRowAtIndexPath indexPath: NSIndexPath, withSender sender: AnyObject?) -> Bool {
    return action == #selector(NSObject.copy(_:)) || action == #selector(MyCell.customMenuItemTapped(_:))
}

override func tableView(tableView: UITableView, performAction action: Selector, forRowAtIndexPath indexPath: NSIndexPath, withSender sender: AnyObject?) {
    switch action {
    case #selector(NSObject.copy(_:)):
        // implement copy here
    default:
        assertionFailure()
    }
}

Notes:

• This uses the new Swift 3 #selectors.
• See this answer for info on how to implement copy.