Add one year in current date PYTHON

Question

I have fetched a date from database with the following variable

{{ i.operation_date }}

Answer 1

AGSM's answer shows a convenient way of solving this problem using the python-dateutil package. But what if you don't want to install that package? You could solve the problem in vanilla Python like this:

from datetime import date

def add_years(d, years):
    """Return a date that's `years` years after the date (or datetime)
    object `d`. Return the same calendar date (month and day) in the
    destination year, if it exists, otherwise use the following day
    (thus changing February 29 to March 1).

    """
    try:
        return d.replace(year = d.year + years)
    except ValueError:
        return d + (date(d.year + years, 1, 1) - date(d.year, 1, 1))

If you want the other possibility (changing February 29 to February 28) then the last line should be changed to:

        return d + (date(d.year + years, 3, 1) - date(d.year, 3, 1))