Java: Checking if a bit is 0 or 1 in a long

Question

What method would you use to determine if the the bit that represents 2^x is a 1 or 0 ?

Answer 1

I wonder if:

  if (((value >>> x) & 1) != 0) {

  }

.. is better because it doesn't matter whether value is long or not, or if its worse because it's less obvious.

Tom Hawtin - tackline Jul 7 at 14:16