int a = 5, b;
post increment : b = a++; : a is first transferred to b and then a is incremented, so now b is 5, and a is 6 The effect is b = a; a = a + 1;
pre increment: b = ++a; : first a is incremented and then the result is transferred into b, so now a is 7 and also b is 7. The effect is a = a + 1; b = a
a++ and ++a staying independently act in the similar way. In the loop examples you have presented, the increment operators is not associated in any expression, and are independent. Therefore these two in this particular implementation is identical.
