Simple URL GET/POST function in Python

Question

I can\'t seem to Google it, but I want a function that does this:

Accept 3 arguments (or more, whatever):

• URL
• a dictionary of params

Answer 1

import urllib

def fetch_thing(url, params, method):
    params = urllib.urlencode(params)
    if method=='POST':
        f = urllib.urlopen(url, params)
    else:
        f = urllib.urlopen(url+'?'+params)
    return (f.read(), f.code)


content, response_code = fetch_thing(
                              'http://google.com/', 
                              {'spam': 1, 'eggs': 2, 'bacon': 0}, 
                              'GET'
                         )

[Update]

Some of these answers are old. Today I would use the requests module like the answer by robaple.