Simple URL GET/POST function in Python

Question

I can\'t seem to Google it, but I want a function that does this:

Accept 3 arguments (or more, whatever):

• URL
• a dictionary of params

Answer 1

You could use this to wrap urllib2:

def URLRequest(url, params, method="GET"):
    if method == "POST":
        return urllib2.Request(url, data=urllib.urlencode(params))
    else:
        return urllib2.Request(url + "?" + urllib.urlencode(params))

That will return a Request object that has result data and response codes.