Find the index of a dict within a list, by matching the dict's value

Question

I have a list of dicts:

list = [{\'id\':\'1234\',\'name\':\'Jason\'},
        {\'id\':\'2345\',\'name\':\'Tom\'},
        {\'id\':\'3456\',\'name\':\'Art\'}]         


        

Answer 1

Here's a function that finds the dictionary's index position if it exists.

dicts = [{'id':'1234','name':'Jason'},
         {'id':'2345','name':'Tom'},
         {'id':'3456','name':'Art'}]

def find_index(dicts, key, value):
    class Null: pass
    for i, d in enumerate(dicts):
        if d.get(key, Null) == value:
            return i
    else:
        raise ValueError('no dict with the key and value combination found')

print find_index(dicts, 'name', 'Tom')
# 1
find_index(dicts, 'name', 'Ensnare')
# ValueError: no dict with the key and value combination found