How to convert a SVG to a PNG with ImageMagick?

Question

I have a SVG file that has a defined size of 16x16. When I use ImageMagick\'s convert program to convert it into a PNG, then I get a 16x16 pixel PNG which is way too small:<

Answer 1

I've solved this issue through changing the width and height attributes of the tag to match my intended output size and then converting it using ImageMagick. Works like a charm.

Here's my Python code, a function that will return the JPG file's content:

import gzip, re, os
from ynlib.files import ReadFromFile, WriteToFile
from ynlib.system import Execute
from xml.dom.minidom import parse, parseString


def SVGToJPGInMemory(svgPath, newWidth, backgroundColor):

    tempPath = os.path.join(self.rootFolder, 'data')
    fileNameRoot = 'temp_' + str(image.getID())

    if svgPath.lower().endswith('svgz'):
        svg = gzip.open(svgPath, 'rb').read()
    else:
        svg = ReadFromFile(svgPath)

    xmldoc = parseString(svg)

    width = float(xmldoc.getElementsByTagName("svg")[0].attributes['width'].value.split('px')[0])
    height = float(xmldoc.getElementsByTagName("svg")[0].attributes['height'].value.split('px')[0])

    newHeight = int(newWidth / width * height) 

    xmldoc.getElementsByTagName("svg")[0].attributes['width'].value = '%spx' % newWidth
    xmldoc.getElementsByTagName("svg")[0].attributes['height'].value = '%spx' % newHeight

    WriteToFile(os.path.join(tempPath, fileNameRoot + '.svg'), xmldoc.toxml())
    Execute('convert -background "%s" %s %s' % (backgroundColor, os.path.join(tempPath, fileNameRoot + '.svg'), os.path.join(tempPath, fileNameRoot + '.jpg')))

    jpg = open(os.path.join(tempPath, fileNameRoot + '.jpg'), 'rb').read()

    os.remove(os.path.join(tempPath, fileNameRoot + '.jpg'))
    os.remove(os.path.join(tempPath, fileNameRoot + '.svg'))

    return jpg